Answer:
Explanation:
Given
Charge density [tex]\sigma =8.90\ \mu C/m^2[/tex]
We know that electric field due to a large flat horizontal sheet is given by
[tex]E=\frac{\sigma }{2\epsilon _0}[/tex]
where [tex]\epsilon =[/tex]space Permittivity
[tex]\epsilon _0=8.85\times 10^{-12}\ C^2/N.m^2[/tex]
substituting values we get
[tex]E=\frac{8.90\times 10^{-6}}{2\times 8.85\times 10^{-12}}[/tex]
[tex]E=5.02\times 10^{5}\ N/C[/tex]
