Answer:
Initial temperature of water was 34,3°C
Explanation:
The heat absorbed in the process (Q) can be written as:
Q = mcΔT
Where the heat is 5,91x10⁵J, m is mass of water (2150g), c is specific heat of water (4,184J/g°C). And ΔT is change in temperature (100°C - x). Replacing:
5,91x10⁵J = 2150g×4,184J/g°C×(100°C - x)
5,91x10⁵J = 899560J - 8995,6J/°Cx
-3,0856x10⁵J = - 8995,6J/°Cx
34,3°C = x
Thus, initial temperature of water was 34,3°C
I hope it helps!
