Answer:
Step-by-step explanation:
They are two ways:
METHOD 1:
Use the Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
On the square, the legs are the sides of the square, and the hypotenuse is the diagonal of the square.
We have two the same legs = 6.
Let d - diagonal
Substitute:
[tex]6^2+6^2=d^2\\\\d^2=36+36\\\\d^2=(36)(2)\to d=\sqrt{(36)(2)}\\\\d=\sqrt{36}\cdot\sqrt2\\\\d=6\sqrt2[/tex]
METHOD 2:
Use the formula of a diagonal of a square:
[tex]d=s\sqrt2[/tex]
d - diagonal
s - side
We have s = 6.
Substiute:
[tex]d=6\sqrt2[/tex]