Answer:
86 in
Step-by-step explanation:
We are given that
x=3in and y=4 in
Sides of polygon are
[tex]4y,4x^2-3y^2,3x,x^2+2y^2,2y^2[/tex]
We have to find the perimeter of polygon.
Perimeter of polygon=Sum of all sides of polygon
Perimeter of polygon=[tex]4y+4x^2-3y^2+3x+x^2+2y^2+2y^2=5x^2+y^2+3x+4y[/tex]
Substitute the values of x and y
Then, we get
Perimeter of polygon=[tex]5(3)^2+(4)^2+3(3)+4(4)[/tex]
Perimeter of polygon=86 in
Hence, the perimeter of polygon=86 in
