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Water flows through a pipe of
radius 0.0250 m at 1.50 m/s.
The pipe narrows to a radius of
0.0100 m. What is the new
velocity of the water?
(Unit = m/s)​

Respuesta :

MathPhys

Answer:

9.38 m/s

Explanation:

Mass is conserved.

m₁ = m₂

ρ₁ Q₁ = ρ₂ Q₂

Assuming no change in density:

Q₁ = Q₂

v₁ A₁ = v₂ A₂

v₁ π r₁² = v₂ π r₂²

v₁ r₁² = v₂ r₂²

Plugging in values:

(1.50 m/s) (0.0250 m)² = v (0.0100 m)²

v = 9.38 m/s

Answer:0.00295 m/s

Explanation:

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