Answer:
a)K=385.86 N/m
b)A=0.088 m
Explanation:
Given that
m = 220 gm = 0.22 kg
t= 0.15 s
Total energy TE= 1.5 J
We know that time period in the SHM given as
[tex]T=\dfrac{2\pi}{\omega}[/tex]
[tex]\omega=\dfrac{2\pi}{T}[/tex]
[tex]\omega=\dfrac{2\times \pi}{0.15}[/tex]
ω=41.88 rad/s
We know that
ω² m = K
K=Spring constant
[tex]K = 41.88^2 \times 0.22 \ N/m[/tex]
K=385.86 N/m
[tex]TE=\dfrac{1}{2}KA^2[/tex]
A=Amplitude
[tex]A=\sqrt{\dfrac{2\times TE}{K}}[/tex]
[tex]A=\sqrt{\dfrac{2\times 1.5}{385.86}}[/tex]
A=0.088 m
