Respuesta :
Answer:
Explanation:
Given
Two capacitor are identical such that one is empty and other is filled with dielectric
Inserting a dielectric increases the capacitance k times if k is the dielectric strength
Empty capacitor [tex]C_1=C[/tex]
Dielectric capacitor [tex]C_2=k\times C=3.6C[/tex]
[tex]V_1=24 V[/tex]
Energy stored in first capacitor [tex]E_1=\frac{1}{2}CV^2=\frac{1}{2}\times C(24)^2[/tex]
Energy stored in second capacitor [tex]E_2=\frac{1}{2}\times 3.6C\times (V)^2[/tex]
[tex]E_1=E_2[/tex]
[tex]\frac{1}{2}\times C(24)^2=\frac{1}{2}\times 3.6C\times (V)^2[/tex]
[tex]V=12.64\ V[/tex]
