Respuesta :
Answer:
(D)
Explanation:
Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.
When an acid donates a proton, it changes into a base which is known as its conjugate base.
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.
Thus,
(A) [tex]H^+[/tex] does not have any conjugate base.
(B) [tex]NH_3[/tex] is a base and does not have any conjugate base.
(C) The conjugate base of the acid, [tex]H_2PO_4^{-}[/tex] is [tex]HPO_4^{2-}[/tex] but not vice versa.
(D) The conjugate base of the acid, [tex]HCO_3^-[/tex] is [tex]CO_3^{2-}[/tex]
(E) [tex]CH_3COOH\ and\ CH_3COO^{-}[/tex] is a acid conjugate base pair.
Hence, (D) is the answer.
The pair of substances in which an acid is listed followed by its conjugate base - D) HCO₃⁻, CO₃²⁻
According to Brønsted–Lowry's definition of acids and bases, a conjugate acid-base pair consists of two substances that differ only by the presence of a proton (H⁺).
- A conjugate acid is formed when a proton is added to a base,
base + H⁺----------------> conjugate acid
- a conjugate base is formed when a proton is removed from an acid
acid------------> conjugate base + H⁺
For the given option:
Option D.
- HCO₃------------------>CO32- + H+
acid conjugate base
Option A.
- H+ + Cl- --> HCl
no acid-base pair here
Option B.
- NH₃ + H⁺ --> NH₄⁺
C. ammonia (NH3) acting as a base
Option C.
- HPO₄²⁻ + H⁺ --> H₂PO₄⁻
. hydrogen phosphate acting as a base
Option E.
- CH₃COOH + H⁺---> CH₃COOH₂⁺
Acetic acid (CH3COOH) is accepting H⁺ base, and CH₃COOH₂⁺ is its conjugate acid
Thus, the pair of substances in which an acid is listed followed by its conjugate base - D) HCO3-, CO32-
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