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We have an urn with 3 green and 4 yellow balls. We choose 2 balls randomly without replacement. Let A be the event that we have two different colored balls in our sample. a. Describe a possible sample space with equally likely outcomes and the event A in your sample space. b. Compute P(A)

Respuesta :

Answer:

Step-by-step explanation:

Urn has 3 green and 4 yellow

we choose 2 balls randomly

so samples  space for this selection is

[tex]\left [ \left ( Y,G\right ),\left ( G,Y\right ),\left ( G,G\right ),\left ( Y,Y\right )\right ][/tex]

Event A is choosing differently colored ball form sample space

P(A)=Probability of event (G,Y)+Probability of event (Y,G)

[tex]=\frac{^3C_1\times ^4C_1}{7\times 6}+\frac{^4C_1\times ^3C_1}{7\times 6}[/tex]

[tex]=\frac{4}{7}[/tex]

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