Answer:
0 ≤ z ≤ 9, x^2 + y^2 ≤ 9
Step-by-step explanation:
z = 9
radius = 3
The region that lies on or below has a plane z= 9
This means that z ≤ 9
The region that lies on or above the disk in the xy plane is described by z ≥ 0
The combination inequality is 0 ≤ z ≤ 9
To restrict the disk centred at the origin with radius 3 is to restrict the x and y values. We have
x^2 + y^2 ≤ r^2
x^2 + y^2 ≤ 3^2
x^2 + y^2 ≤ 9
The full set of inequalities is
0 ≤ z ≤ 9, x^2 + y^2 ≤ 9
The pair of inequalities to describe the region occupied by the solid cylinder is therefore;
The region that lies on or below a plane z= 9 can be represented as; z ≤ 9
The region that lies on or above the disk in the xy plane is described and represented as; z ≥ 0
Ultimately, 0 ≤ z ≤ 9
To restrict the disk centred at the origin with radius 3 means to restrict the x and y values. We have
The pair of inequalities to describe the region occupied by the solid cylinder is therefore;
0 ≤ z ≤ 9, x² + y² ≤ 9.
Read more on plane geometry:
https://brainly.com/question/24855025
