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A 760 N man stands in the middle of a frozen pond of radius 6.0 m. He is unable to get to the other side because of a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 1.2 kg physics textbook horizontally toward the north shore, at a speed of 6.0 m/s. How long does it take him to reach the south shore?

Respuesta :

Answer:

Explanation:

Given

weight of man [tex]W=760 N[/tex]

mass of man [tex]m_1=\frac{760}{g}=76\ kg[/tex]

radius of pond [tex]r=6\ m[/tex]

mass of textbook [tex]m_2=1.2\ kg[/tex]

speed of text book [tex]v_2=6\ m/s[/tex]

Let speed at which man recoils is [tex]v_1[/tex]

Initially momentum is zero as man is at rest

Conserving momentum

[tex]0=m_1v_1+m_2v_2[/tex]

[tex]0=76\times v_1+1.2\times 6[/tex]

[tex]v_1=-0.1\ m/s[/tex]

i.e. 0.1 m/s towards south

time taken to reach other side in absence of friction is given by

[tex]t=\frac{distance}{speed}[/tex]

[tex]t=\frac{6}{0.1}[/tex]

[tex]t=60 s\approx 1\ minute[/tex]        

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