Answer:0.253Joules
Explanation:
First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.
F = ke where;
F is the force
k is spring constant = 34N/m
e is the extension = 0.12m
F = 34× 0.12 = 4.08N
To get work done,
Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.
Work done = Force × Distance
Since F = 4.08m, distance = 0.062m
Work done = 4.08 × 0.062
Work done = 0.253Joules
Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules
The total work done, to stretch the spring at a distance of 0.062 m, is 0.253 Joules.
Given that the spring constant is 34 N/m and its extension is 0.12 m.
The applied force to stretch the spring is given by Hooke's Law.
[tex]F = ke[/tex]
Where F is the force, k is the spring constant and e is the extension of the spring.
[tex]F = 34\times 0.12[/tex]
[tex]F = 4.08 \;\rm N[/tex]
Thus the applied force is 4.08 N.
The work done to stretch the spring will be equal to the product of applied force and distance.
[tex]W = F\times d[/tex]
[tex]W = 4.08 \times 0.062[/tex]
[tex]W = 0.253 \;\rm J[/tex]
Hence the total work done, to stretch the spring at a distance of 0.062 m, is 0.253 Joules.
To know more about the work, follow the link given below.
https://brainly.com/question/3902440.
