Respuesta :
Answer:
Moles of mercury = 0.00484 mol.
Moles of oxygen = 0.00481 mol.
The empirical formula is = [tex]HgO[/tex]
Explanation:
[tex]Moles =Given\ mass \times {Molar\ mass}[/tex]
Mass of mercury = 0.971 g
Molar mass of mercury = 200.59 g/mol
Moles of mercury = [tex]\frac{0.971\ g}{200.59\ g/mol}[/tex] = 0.00484 mol.
Since, the oxide contains only mercury and oxygen. SO,
Mass of O in the sample = Total mass - Mass of Hg
Mass of the sample = 1.048 g
Mass of O in sample = 1.048 g - 0.971 g = 0.077 g
Molar mass of oxygen = 15.999 g/mol
Moles of oxygen = [tex]\frac{0.077\ g}{15.999\ g/mol}[/tex] = 0.00481 mol.
Taking the simplest ratio for Hg and O as:
0.00484 : 0.00481
= 1 : 1
The empirical formula is = [tex]HgO[/tex]
