The elastic potential energy of the spring is 0.31 J
Explanation:
The elastic potential energy of a spring is given by
[tex]E=\frac{1}{2}kx^2[/tex]
where
k is the spring constant
x is the compression/stretching of the spring
For the spring in this problem, we have:
k = 500 N/m (spring constant)
x = 0.035 m (compression)
Substituting, we find the elastic potential energy:
[tex]E=\frac{1}{2}(500)(0.035)^2=0.31 J[/tex]
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