Respuesta :
Answer :
The chemical symbol for the ion is, [tex]Ar^+[/tex]
The total number of electrons present in the ion = 17
There is no 3d electrons are in the ion.
Explanation :
Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom are determined by the electronic configuration.
Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.
As per question the electronic configuration of cation is,
[tex]1s^22s^22p^63s^23p^5[/tex]
As 1 electron is added in this configuration then the electronic configuration of element will be:
[tex]1s^22s^22p^63s^23p^6[/tex]
The total number of electrons = [2 + 2 + 6 + 2 + 6] = 18
The atom having atomic number 18 is argon.
The chemical symbol for the ion is, [tex]Ar^+[/tex]
The total number of electrons present in the ion = [2 + 2 + 6 + 2 + 5] = 17
As we know that argon is a noble gas. So, argon do not possess d-orbitals.
Thus, there is no 3d electrons are in the ion.
The chemical symbol for the cation is Ar⁺¹.
The ion has 17 electrons.
The ions has no 3d electrons.
The atomic cation is +1.
The electronic configuration of the cation is as follows:
1s² 2s² 2p⁶ 3s² 3p⁵
The number of electron is equals to the number of proton for an electronically neutral atom.
In this case the atoms has lost one electron to become a cations.
Therefore, the electronically neutral state of the atom is represented as follows:
1s² 2s² 2p⁶ 3s² 3p⁶
The atomic number of the neutral atom = 2 + 2 + 6 + 2 + 6 = 18
Therefore, the elements is Argon and the symbol for the ion is Ar⁺¹. Since it gave out one electron.
1s² 2s² 2p⁶ 3s² 3p⁵ is the electronic configuration of the ion. It has lost one electron, the number of electron of the ion is 2 + 2 + 6 + 2 + 5 = 17.
The atom does not have a 3d electron in the ion.
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