The gravitational field strength on the surface of Jupiter is 25.6 N/kg
Explanation:
The gravitational field strength at the surface of a planet is given by the equation:
[tex]g=\frac{GM}{R^2}[/tex]
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
The planet in this problem is Jupiter, so we have:
[tex]M=1.90\cdot 10^{27} kg[/tex] is the mass
[tex]R=6.99\cdot 10^7 m[/tex] is the radius
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
Substituting, we find:
[tex]g=\frac{(6.67\cdot 10^{-11})(1.90\cdot 10^{27})}{(6.99\cdot 10^7)^2}=25.9 N/kg[/tex]
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