Answer:
13.86 MJ
Explanation:
[tex]5100 rev/min = 5100 rev/min * 2\pi rad/rev * 1/60 min/s = 534.1 rad/s [/tex]
Since flywheel is a solid disk, its moment of inertia can be calculated with the following formula:
[tex]I = mr^2/2[/tex]
where m = 540kg is the mass and r = 0.6m is the radius
[tex]I = 540*0.6^2/2 = 97.2 kgm^2[/tex]
(a) the kinetic energy stored in the flywheel can be calculated
[tex]E_k = I\omega^2/2 = 97.2*534.1^2/2 = 13862254.17 J[/tex] or 13.86 MJ