A nugget of gold with a mass of 521 g is added to 50.0 mL of water. The water level rises to a volume of 77.0 mL. What is the density of the gold?

A). 10.4g/mL
B). 6.77g/mL
C). 1.00g/mL
D). 0.0518g/mL
E). 19.3g/mL

Respuesta :

E: 77-50=27 (the volume of the gold) 521/27=19.3

The statement, that describes the density of the gold is "19.3g/mL."

What is density?

A substance's density is defined as its mass per unit volume. In other words, density is the ratio of mass to volume.

[tex]Density\;=\;\frac{mass}{volume}[/tex]

Now, the volume of water,

= 77.0 mL - 50.0 mL

= 27.0 mL

Density of the gold comes out to be,

[tex]=\frac{521\;g}{27.0\;mL} \\\\= 19.296\;g/mL[/tex]

≈ 19.3 g/mL

Hence the correct option is E.

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