Answer:
Step-by-step explanation:
Given is a function in f as
[tex]f(x) = log_{10} x[/tex]
We can change base to e for our convenience for finding derivatives
[tex]f(x) = log_{e} x ( log_{10} e)[/tex]
The second term is a constant with value = 0.434294
So f(x) = 0.434294 ln x
Now differentiate with respect to x two times
I derivative = [tex]f'(x) = \frac{0.434294}{x} \\f"(x) = - \frac{0.434294}{x^2}[/tex]
Note: We can leave as log e to base 10 also without converting into actual values.
