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Two cyclists, 90 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other.
If they meet 3 hr later, at what average speed is each cyclist traveling?

Respuesta :

Speed of cyclist 1  = 10 mile per hour

Speed of cyclist 2  = 20 mile per hour

Step-by-step explanation:

Distance between cyclists = 90 miles

Let v be the speed of one cyclist, speed of other cyclist is twice the speed of first cyclist.

Speed of second cyclist = 2 x v

Time taken by them to meet = 3 hr

Since they are moving towards each other, relative velocity is given by

                Relative velocity = v + 2v = 3v

We have

       Distance = Time x Velocity

       90 = 3 x 3 v

           9v = 90

             v = 10 mile per hour

Speed of cyclist 1 = v = 10 mile per hour

Speed of cyclist 2 = 2v = 20 mile per hour

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