Respuesta :
Answer:
0.0872 or 8.72%
Step-by-step explanation:
The probability of a random molding being defective is given by the probability of the foreman remembering to shut off the injection machine (74%) multiplied by the probability of defects (3%), added to the probability of the foreman forgetting to shut off the injection machine (26%) multiplied by the probability of defects in this scenario (25%):
[tex]P = (0.74*0.03)+(0.26*0.25)\\P=0.0872 = 8.72\%[/tex]
The probability that a randomly selected molding is defective is 0.0872 or 8.72%
The probability a randomly selected molding is defective is 0.0872 or 8.72%.
Given
A foreman for an injection-molding firm admits that on 26% of his shifts, he forgets to shut off the injection machine on his line.
This causes the machine to overheat, increasing the probability that a defective molding will be produced during the early morning run from 3% to 25%.
Probability;
Experimental probability is what actually happens. Using the coin example, flipping the coin 100 times, it could actually land on heads 100 times or any number of times from 0 to 100.
Let D be the event of being Defective.
When he forgets to shut off the machine 52% of the time;
[tex]\rm P (D) = 0.25 \times 0.26= 0.065[/tex]
When he does not forget to shut off the injection machine ( 1- 0.26= 0.74) or 74 % of the time;
[tex]\rm P (D) = 0.74 \times 0.03= 0.022[/tex]
Therefore,
Total Probability of Defect = Probability of Defect When forgetting + Probability of Defect when not forgetting
Total Probability of Defect = 0.065 + 0.022 = 0.0872 or 8.72%
Hence, the probability a randomly selected molding is defective is 0.0872 or 8.72%.
To know more about probability click the link given below.
https://brainly.com/question/743546
