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A certain molecular compound M has a solubility in acetone of 0.737g/mL at 10.°CCalculate the mass of M that's dissolved in 9.0L of a saturated solution of M in acetone at this temperature.Be sure your answer has the correct unit symbol and number of significant digits.

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Answer:

6633 grams of M are dissolved in 9L

Explanation:

If the compound M has a solubility in acetone of 0.737 g/mL, means that in 1 mLof solution, 0.737 grams of solute is dissolved.

Let's make a rule of three:

9 L = 9000 mL

In 1 mL ___ 0.737 g of M is dissolved

In 9000 mL ___ (9000 . 0.737) /1 = 6633 grams

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