Answer:[tex]F_2=16\times F_1[/tex]
Explanation:
Given
Force of repulsion between two charge particle is given by force F
Electrostatic force is given by
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
where [tex]q_1[/tex] and [tex]q_2[/tex] is the charges of particle
r=distance between charge particle
[tex]=\frac{kq^2}{r^2}[/tex]when charges are doubled and distance is reduced to half
i.e. q become 2 q and r becomes 0.5 r
[tex]F_2=\frac{k(2q)^2}{(0.5r)^2}[/tex]
[tex]F_2=\frac{kq^2}{r^2}\times 4\times 4[/tex]
[tex]F_2=16\times F_1[/tex]
