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2 3 ​ y−3+ 3 5 ​ zstart fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6y, equals, 6 and z=3z=3z, equals, 3.

Respuesta :

profantoniofonte

Answer:

11

Step-by-step explanation:

1) This expression can be solved simply by plugging in the given conditions y=6 and z=3.

[tex]\frac{3}{2}y-3+\frac{5}{3}z\:When\: y=6\:z=3 \Rightarrow \\\frac{3}{2}*(6)-3+\frac{5}{3}*(3) \Rightarrow 9-3+5=11[/tex]

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