Answer: The derivative would be [tex]y'=e^x(1+x)+4e^{-x}[/tex]
Step-by-step explanation:
Since we have given that
[tex]y=xe^x-4e^{-x}[/tex]
as we know the product rule:
[tex]xe^x=x'e^x+xe^x'=e^x+xe^x[/tex]
so, it becomes,
[tex]y'=e^x(1+x)-4\times -1e^{-x}\\\\y'=e^x(1+x)+4e^{-x}[/tex]
Hence, the derivative would be
[tex]y'=e^x(1+x)+4e^{-x}[/tex]