Answer: The derivative of the given function is [tex]f'(x)=\dfrac{2}{x}e^{\frac{1}{x^2}}[/tex]
Step-by-step explanation:
Since we have given that
[tex]f(x)=e^{\frac{-1}{x^2}}[/tex]
We will derivative it:
So, it becomes,
[tex]f'(x)=-e^{\frac{1}{x^2}}\times (\frac{1}{x^2})'\\\\f'(x)=-e^{\frac{1}{x^2}}\times \dfrac{-2}{x}\\\\f'(x)=\dfrac{2}{x}e^{\frac{1}{x^2}}[/tex]
Hence, the derivative of the given function is [tex]f'(x)=\dfrac{2}{x}e^{\frac{1}{x^2}}[/tex]
