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If i have 2.9liters of gas at a pressure of 5 atm and a temperature of 50 what will be the temperature of the gas if i decrease the volume of the gas to 2.4 liters and decrease the pressure to 3 atm

Respuesta :

Neetoo

Answer:

T₂= FINAL TEMPERATURE  = 160.4 K

Explanation:

Given data:

Initial volume of gas = 2.9 L

Initial pressure = 5 atm

Initial temperature = 50°C

Final volume = 2.5 L

Final pressure = 3 atm

Final temperature = ?

Solution:

First of all we will convert the temperature in kelvin.

273+ 50 = 323 K

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put values in formula.

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂ T₁ / P₁V₁

T₂ = 3 atm × 2.4 L × 323 K / 5 atm × 2.9  L  

T₂ = 2325.6 atm. L. K / 14.5 atm.L

T₂ = 160.4 K

ajeigbeibraheem

The final temperature of the gas is 160.39 K

From the information given;

  • the initial volume (V1) = 2.9 liters
  • initial pressure (P1) = 5 atm
  • initial temperature (T1) = 50 ° C = (273 + 50)K = 323 K
  • the final volume(V2) = 2.4 liters
  • final pressure(P2) = 3 atm
  • final temperature (T2) = ???

By using the combined gas law to determine the final temperature, we have:

[tex]\mathbf{\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}}[/tex]

By cross multiplying;

[tex]\mathbf{P_1V_1T_2= P_2V_2T_1}}[/tex]

Making the final temperature the subject, we have:

[tex]\mathbf{T_2=\dfrac{ P_2V_2T_1}{P_1V_1}}[/tex]

[tex]\mathbf{T_2=\dfrac{ 3 \ atm \times 2.4 L \times 323 \ K}{5 \ atm \times 2.9 \ liters}}[/tex]

[tex]\mathbf{T_2=160.39 \ K}[/tex]

Therefore, we can conclude that the final temperature of the gas is 160.39 K

Learn more about gas law here:

https://brainly.com/question/12669509?referrer=searchResults

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