Answer:
4x²y⁴
Step-by-step explanation:
We are given: [tex]\sqrt[3}{(8x^3y^9)^2}[/tex]
Since, [tex]$ \sqrt[3]{a} = a^{\frac{1}{3}} $[/tex].
Therefore, we get:
[tex]$ (8x^3y^9)^{\frac{2}{3}} $[/tex]
Also, we have:
[tex]$ (a^b)^c = a^{b.c} $[/tex]
⇒ [tex]$ (2^3)^{\frac{2}{3}}. (x^3)^{\frac{2}{3}}. ((y^2)^3)^{\frac{2}{3}} $[/tex]
⇒ [tex]$ 2^2 . x . (y^2)^2 $[/tex]
⇒ [tex]$ 4. x. y^4 $[/tex] which is the required answer.
