Answer:
It would take approximately 8.82 sec for a penny to strike the person.
Step-by-step explanation:
Given:
Height of the building = 1250 feet
Height of the person = 6 feet.
Modeled equation is [tex]h=-16t^2+1250[/tex]
We need to find the time required 't' for the penny to strike the person.
Solution:
to find the time required 't' for the penny to strike the person we will substitute;
h ⇒ height of the person.
So we get;
[tex]6=-16t^2+1250[/tex]
Now Combining the like terms we get;
[tex]16t^2=1250-6\\\\16t^2=1244[/tex]
Dividing both side by 16 using division property we get;
[tex]\frac{16t^2}{16} =\frac{1244}{6}\\\\t^2 = 77.75[/tex]
Now taking square root on both side we get;
[tex]\sqrt{t^2}= \sqrt{77.75}\\\\t \approx 8.82 secs[/tex]
Hence It would take approximately 8.82 sec for a penny to strike the person.
It will take 8.817596 seconds.
Given equation is: [tex] h=-16t^2+1250[/tex].
To strike a 6 feet tall person the penny must be at the height = h = 6 feet.
So we solve the equation for h = 6.
[tex]6=-16t^2+1250\\ 16t^2=1244\\ t^2=77.75\\ t=\sqrt{77.75}\\ t=8.817596[/tex]
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