Which equation is the inverse of 2(x – 2)2 = 8(7 + y)? –2(x – 2)2 = –8(7 + y) y = one-fourth x squared minus x minus 6 y = negative 2 plus-or-minus StartRoot 28 + 4 x EndRoot y = 2 plus-or-minus StartRoot 28 + 4 x EndRoot

Respuesta :

Answer:

[tex]y=2\pm\sqrt{28+4x}[/tex]

Step-by-step explanation:

we have

[tex]2(x-2)^2=8(7+y)[/tex]  

step 1

Exchange the variables x for y and y for x

[tex]2(y-2)^2=8(7+x)[/tex]  

step 2

Isolate the variable y

Divide by 2 both sides

[tex](y-2)^2=4(7+x)[/tex]

square root both sides

[tex]y-2=\pm\sqrt{4(7+x)}[/tex]

Adds 2 both sides

[tex]y=2\pm\sqrt{4(7+x)}[/tex]

Apply distributive property right side

[tex]y=2\pm\sqrt{28+4x}[/tex] ---> inverse function

y = 2 plus-or-minus StartRoot 28 + 4 x EndRoot

Answer:D

Step-by-step explanation:No Cap