Answer:
20.85 years
Explanation:
2.61 km = 2610 m
2.07 kW = 2070 W
First we need to calculate the potential energy required to take m = [tex]5.32 * 10^7[/tex] kg of rain cloud to an altitude of 2610 m is
[tex]E = mgh = 5.32 * 10^7 * 9.81 * 2610 = 1.4*10^{12}J[/tex]
With a P = 2070 W power pump, this can be done within a time frame of
[tex]t = E/P = \frac{1.4*10^{12}}{2070} = 658037739 s[/tex]
or 658037739/(60*60) = 182788 hours or 182788 / 24 = 7616 days or 7616 / 365.25 = 20.85 years
