Respuesta :
Answer:
187.44 g
Explanation:
Calculation of the moles of [tex]Fe_2O_3[/tex] as:-
Mass = 268 g
Molar mass of iron(III) oxide = 159.69 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{268\ g}{159.69\ g/mol}[/tex]
[tex]Moles= 1.67825\ mol[/tex]
According to the formula, 1 mole of iron(III) oxide has 2 moles of iron.
Also,
1.67825 mole of iron(III) oxide has [tex]2\times 1.67825[/tex] moles of iron.
Moles of iron = 3.3565 moles
Molar mass of iron = 55.845 g/mol
Mass=Moles*Molar mass = [tex]3.3565\times 55.845\ g[/tex] = 187.44 g
187.44 g of iron can be obtained from a 268-g sample of iron(III) oxide.
Mass is the amount of the weight occupied by the substance. The mass of iron that can be obtained from a sample of iron(III) oxide is 187.44 gm.
What is mass?
Mass is the product of the moles of the substance and of the molar mass of the substance.
The moles of a sample of iron(III) oxide can be calculated as:
[tex]\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{268}{159.69}\\\\&= 1.678\;\rm mol\end{aligned}[/tex]
Hence, 1.678 mol is the moles of iron(III) oxide.
If 1 mole of iron(III) oxide contains 2 moles of Iron then 1.678 mol of the sample will have 3.356 moles of iron.
Mass of iron can be calculated as:
[tex]\begin{aligned}\rm mass &=\rm moles \times molar \; mass\\\\&= 3.35 \times 55.84\\\\&= 187.44\;\rm gm\end{aligned}[/tex]
Therefore, 187.44 gm of iron is present in the sample of iron(III) oxide.
Learn more about mass here:
https://brainly.com/question/6974263
