Step-by-step explanation:
Here f (x) is a linear function.
That is
f(x) = ax + b
Given that f (−2) = 3 , and f (1) = 0
f(-2) = a x -2 + b
-2a + b = 3 --------------------eqn 1
f(1) = a x1 + b
-a + b = 0 --------------------eqn 2
eqn 1 - eqn 2
-2a - (-a) = 3 - 0
-a = 3
a = -3
Substituting in eqn 2
-(-3) + b = 0
b = -3
f(x) = -3x + (-3)
f(x) = -3x - 3
Equation for f(x) is -3x - 3
