Answer:
D(5,-8)
Step-by-step explanation:
The given point is (-3,-2)
When we reflect in the line y=k, we use the rule (x, 2k-y)
This implies that:
[tex](-3, - 2)\to (-3, 2*-5--2)[/tex]
[tex](-3, - 2)\to (-3, - 8)[/tex]
When we reflect in the line x=k, we use the rule
[tex](x,y)\to (2k-x,y)[/tex]
Now we have x=1
This implies that:
[tex]( - 3, - 8)\to (2 \times 1- - 3, - 8)[/tex]
[tex]( - 3, - 8)\to (5, - 8)[/tex]
