A 3 kg mass at rest on the floor is attached to a string which goes vertically to a pulley. A weight is attached to the other end of the string and released. If the 3 kg mass rises 50 cm in 1 s, find is the value of the other mass.

Respuesta :

Answer:

M = 3.68 Kg

Explanation:

given,

mass on the floor, m = 3 Kg

mass raised to, s = 50 cm

time,t = 1 s

using equation of motion

[tex]s = u t + \dfrac{1}{2}at^2[/tex]

s is the displacement .

initial speed = 0

[tex]0.5=\dfrac{1}{2}\times a\times 1^2[/tex]

   a = 1 m/s²

acceleration in terms of mass and gravity is given as

 a = m g

[tex]a = \dfrac{M-m}{M+m}\times g[/tex]

M is the mass of the block hanging

[tex]1= \dfrac{M-3}{M+3}\times 9.8[/tex]

     M + 3 = 9.8 M - 29.4

      8.8 M = 32.4

       M = 3.68 Kg

The other mass is equal to M = 3.68 Kg