Answer:
(a) 20.4 rad/s
(b) 3.09 Nm
Explanation:
Given:
Δθ = 6.71 rev = 42.2 rad
ω₀ = 0 rad/s
t = 4.13 s
Find: ω
Δθ = ½ (ω + ω₀) t
42.2 rad = ½ (ω + 0 rad/s) (4.13 s)
ω = 20.4 rad/s
Find: α
Δθ = ω₀ t + ½ αt²
42.2 rad = (0 rad/s) (4.13 s) + ½ α (4.13 s)²
α = 4.94 rad/s²
∑τ = Iα
τ = ½ m r² α
τ = ½ (2.33 kg) (0.733 m)² (4.94 rad/s²)
τ = 3.09 Nm
