You are making a sculpture that is a pyramid with a square base. You want the height of the pyramid to be 4 inches less than the length of a side of the base. You want the volume of the sculpture to be 200 cubic inches. Write a function that gives the volume V of the sculpture in terms of x.

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Answer:

The required function that gives the volume V in terms of x is [tex]V=\dfrac{x^3}{3}-\dfrac{4x^2}{3}[/tex].

Step-by-step explanation:

Consider the provided information.

The height of the pyramid to be 4 inches less than the length of a side of the base.

Let the length of a side of the base is = x

Thus, the height of the pyramid = x-4

The volume of the sculpture is 200 cubic inches

Volume of a pyramid is: [tex]V=\dfrac{1}{3} \text{Area of Base}\times\text{Height}[/tex]

The base of pyramid is square.

So, the area of base = [tex]x^2[/tex]

Substitute the respective values in the above formula.

[tex]V=\dfrac{1}{3}\times(x^2)\times(x-4)[/tex]

[tex]V=\dfrac{1}{3}\times(x^3-4x^2)[/tex]

[tex]V=\dfrac{x^3}{3}-\dfrac{4x^2}{3}[/tex]

Hence, the required function that gives the volume V in terms of x is [tex]V=\dfrac{x^3}{3}-\dfrac{4x^2}{3}[/tex].