Answer:
x = 9.5 m
Step-by-step explanation:
Given:
This problem is based on 2D motion kinematics equations:
[tex]V_0 = 12 m/s[/tex]
[tex]\theta = 20^0[/tex]
[tex]g=9.8 m/s^2[/tex]
At maximum height:
[tex]V_y = 0[/tex]
Components of initial velocity:
[tex]V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s[/tex]
[tex]V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s[/tex]
To find time to reach maximum height:
[tex]V_y = V_0y -gt[/tex]
Plugging in the known values:
0 = 4.10 - 9.8t
[tex]t = \frac{-4.10}{-9.8}[/tex]
[tex]t = 0.418 s[/tex]
Total time = 2t = 2(0.418) = 0.836 s
to find horizontal distance covered:
[tex]x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m[/tex]
