Given the equation p = s Subscript 1 Baseline t minus 2 Subscript 2 Baseline t, which equation is solved for t? t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline) t = p minus s Subscript 1 Baseline minus s Subscript 2 t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction
A. t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)
B. t = p minus s Subscript 1 Baseline minus s Subscript 2
C. t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
D. t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction

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Answer:

Option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as [tex]t=\frac{p}{s_{1}-s_{2}}[/tex]

Step-by-step explanation:

Given equation can be written as below:

[tex]p=s_{1}t-s_{2}t[/tex]

Now to solve the equation for t:

[tex]p=s_{1}t-s_{2}t[/tex]

Taking common term t outside on RHS we get

[tex]p=(s_{1}-s_{2})t[/tex]

[tex]\frac{p}{s_{1}-s_{2}}=t[/tex]

Rewritting the above equation as below

[tex]t=\frac{p}{s_{1}-s_{2}}[/tex]

Therefore option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as [tex]t=\frac{p}{s_{1}-s_{2}}[/tex]

Answer:

C. t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

Step-by-step explanation: