Respuesta :
Answer:
[tex]\frac{3}{7} \neq 9[/tex]
Step-by-step explanation:
This question argues that the value [tex]\frac{3}{7}=9[/tex], but this simply isn't true. If one wanted to get the value [tex]9[/tex] from a fraction whose denominator is [tex]7[/tex], one would do the following math:
[tex]9=\frac{x}{7}[/tex]
- [tex]9[/tex] is the same as the fraction [tex]\frac{9}{1}[/tex]. This is because [tex]1[/tex] goes into [tex]9[/tex] nine times.
[tex]\frac{9}{1} = \frac{x}{7}[/tex]
- Now we do something called "cross-multiplication". This is a process of multiplying the numerator of the first fraction by the denominator of the second fraction and vise-versa. There is a way to prove that this method works, but that isn't part of the question, so I'd recommend looking it it up or asking your teacher.
[tex]x=63[/tex]
- By multiplying the numerator of [tex]\frac{9}{1}[/tex], [tex]9[/tex], and the denominator of [tex]\frac{x}{7}[/tex], [tex]7[/tex], our final answer is [tex]63[/tex]. Multiplying the numerator of [tex]\frac{x}{7}[/tex], [tex]x[/tex], and the denominator of [tex]\frac{9}{1}[/tex], [tex]1[/tex], we just get [tex]x[/tex], so this is our final solution for [tex]x[/tex].
[tex]9=\frac{63}{7}[/tex]
Because we proved that [tex]9=\frac{63}{7}[/tex], we know that [tex]9 \neq \frac{3}{7}[/tex].
