Answer:
-1, 2, 5, 8
Step-by-step explanation:
We can use the nth term equation to solve for f(3) and f(4):
[tex]f_n=a_1+(n-1)\cdot{d}[/tex]
Where d is the difference of term 1 and 2:
[tex]d=2-(-1)=3[/tex]
Therefore:
[tex]f_3=-1+(3-1)\cdot{3}=5[/tex]
[tex]f_4=-1+(4-1)\cdot{3}=8[/tex]
