Answer:
True
Explanation:
We are given that all actinoids
General configuration of actinoids series
[tex][Rn]5f^{1-14}6d^{0-1}7s^2[/tex]
Actinoids element are
Ac=89=[tex][Rn]6d^17s^2[/tex]
Th=[tex]90=[Rn]6d^27s^2[/tex]
[tex]Pa=91=[Rn]5f^26d^17s^2[/tex]
[tex]U=92=[Rn]5f^36d^17s^2[/tex]
[tex]Np=93=[Rn}5f^46d^17s^2[/tex]
[tex]Pu=94=[Rn]5f^67s^2[/tex]
[tex]Am=95=[Rn]5f^77s^2[/tex]
[tex]Cm=96[Rn]5f^76d^17s^2[/tex]
[tex]Bk=97=[Rn]5f^97s^2[/tex]
[tex]Cf=98=[Rn]5f^{10}7s^2[/tex]
[tex]Es=99=[Rn]5f^{11}7s^2[/tex]
[tex]Fm=100=[Rn]5f^{12}7s^2[/tex]
[tex]Md=101=[Rn]5f^{13}7s^2[/tex]
[tex]No=102=[Rn]5f^{14}7s^2[/tex]
[tex]Lr=103=[Rn]5f^{14}7s^27p^1[/tex]
We can see that period of actinoid series =7
Electron orbit=period=7
Hence,the statement is true.
