Answer:
[tex]\large\boxed{\text{2.00 mol of KCl}}[/tex]
Explanation:
2K + Cl₂ ⟶ 2KCl
n/mol: 2.00
2 mol of KCl are formed from 2 mol of K
[tex]\text{Moles of KCl} = \text{2.00 mol K} \times \dfrac{\text{2 mol KCl}}{\text{2 mol K}} = \textbf{2.00 mol KCl}\\\\\text{The reaction produces $\large\boxed{\textbf{2.00 mol of KCl}}$}[/tex]
