Answer:
Explanation:
Given
Position vector of location [tex]\vec{r}=-0.3x\hat{i}-0.1y\hat{j}[/tex]
Magnitude of position vector [tex]|\vec{r}|=\sqrt{(-0.3)^2+(-0.1)^2+0}[/tex]
[tex]|\vec{r}|=0.316\ m[/tex]
The electric field at position vector [tex]\vec{r}[/tex] is given by
[tex]\vec{E}=\frac{kq}{r^3}\cdot \vec{r}[/tex]
[tex]\vec{E}=\frac{9\times 10^9\times 2\times 10^{-9}}{0.316^2}\cdot (-0.3x\hat{i}-0.1y\hat{j})[/tex]
[tex]\vec{E}=(180)\cdot (-0.3x\hat{i}-0.1y\hat{j})[/tex]
[tex]\vec{E}=-54x\hat{i}-18y\hat{j}[/tex]
Electric field is
<-54, -18, 0 >
