Answer:
F = 20 N
Explanation:
given,
Impulse, I = 5 Kg.m/s
time of contact, t = 0.25 s
Average force = ?
we know force is equal to change of momentum per unit time.
impulse is equal to change in momentum.
[tex]F = \dfrac{dP}{dt}[/tex]
[tex]F = \dfrac{I}{t}[/tex]
[tex]F = \dfrac{5}{0.25}[/tex]
F = 20 N
The average force exerted by the person on the box is equal to F = 20 N
The average force exerted by the person on the box is of 20 N.
Given data:
The magnitude of impulse is, I = 5.0 kg-m/s.
The time of contact is, t = 0.25 s.
The impulse is defined as the average force applied on an object for a very small period of time.
The standard expression for the impulse is given as,
[tex]I = F_{av.}\times t\\\\F_{av.}=\dfrac{I}{t}[/tex]
Solving as,
[tex]F_{av.}=\dfrac{5}{0.25}\\\\F_{av.}=20\;\rm N[/tex]
Thus, we can conclude that the average force exerted by the person on the box is of 20 N.
Learn more about the impulse from here:
https://brainly.com/question/16980676
