Respuesta :
If we substitute 13 to f(x) and get a value for x, then the two equations will intersect. So,
f(x) = x^2 + 6x +10
13 = x^2 + 6x+ 10
x^2 + 6x - 3 = 0
Solving the quadratic equations:
The roots of the equation is
x = 0.4641 and
x = -6.4541
Therefore, the line will intersect with the quadratic function.
f(x) = x^2 + 6x +10
13 = x^2 + 6x+ 10
x^2 + 6x - 3 = 0
Solving the quadratic equations:
The roots of the equation is
x = 0.4641 and
x = -6.4541
Therefore, the line will intersect with the quadratic function.
the complete question is
Neil is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect? graph of the function f of x equals x squared plus 6x plus 10 g(x) x g(x) 1 3 2 5 3 7
we have
a quadratic function f(x)
[tex] f(x)=x^{2} +6x+10 [/tex]
a linear function g(x)
Let
[tex] A(1,3)\\B(2,5) [/tex]
Find the slope AB
[tex] m=\frac{(y2-y1)}{(x2-x1)} [/tex]
[tex] m=\frac{(5-3)}{(2-1)} [/tex]
[tex] m=2 [/tex]
with [tex] m=2 [/tex] and point A find the equation of the line
[tex] y-y1=m*(x-x1)\\ y-3=2*(x-1)\\ y=2x-2+3\\ y=2x+1\\ g(x)=2x+1 [/tex]
using a graph tool--------> graph f(x) and g(x)
see the attached figure
The graphs will not intersect
therefore
the answer is
No, they will not intersect
