Answer:
[$913.64, $1186.36]
Explanation:
Data provided in the question:
Sample size, n = 10 apartments
Mean monthly rent = $1050
Standard deviation, s = $220
Confidence level = 95%
Now,
Confidence interval = Mean ± [tex][z\frac{s}{\sqrt n}][/tex]
here,
z = 1.96 for 95% confidence level from standard z table
thus,
Confidence interval = $1050 ± [tex][1.96\times\frac{\$220}{\sqrt {10}}][/tex]
or
Confidence interval = $1050 ± 136.36
or
Confidence interval = [$1050 - $136.36, $1050 + $136.36]
or
Confidence interval = [$913.64, $1186.36]