Answer:
42.5W
Explanation:
To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,
[tex]Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}[/tex]
We need to calculate the average power dissipated by the 800\Omega resistor.
Our values are given by:
[tex]P(t)=60 W, 0\leq t<5.0s[/tex]
[tex]P(t)=25 W, 5.0\leq t<10s[/tex]
Aplying the values to the equation we have:
[tex]Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}[/tex]
[tex]Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}[/tex]
[tex]Power_{avg} = 42.5W[/tex]
