Answer:
The value of the turnover number of the enzyme carbonic anhydrase is [tex]1.1318\times 10^5 s^{-1}[/tex].
Explanation:
The turnover number is defined as maximum number of conversions of substrate molecules per second by a single catalytic site for given a concentration of enzyme..
Turn over number = [tex]\frac{R_{max}}{[E]_t}[/tex]
[tex][E]_t[/tex]=catalytic site concentration
[tex]R_{max}[/tex]= Maximum reaction rate
We are given with:
[tex]R_{max}=249 \mu mol/L s=24\times 10^{-6} mol/L s[/tex]
[tex][E]_t=2.20 nmol/L=2.20\times 10^{-9} mol/L[/tex]
Turnover number :
= [tex]\frac{249\times 10^{-6} mol/L s}{2.20\times 10^{-9} mol/L}=1.1318\times 10^5 s^{-1}[/tex]
The value of the turnover number of the enzyme carbonic anhydrase is [tex]1.1318\times 10^5 s^{-1}[/tex].
