Answer:47.78 N
Explanation:
Given
Weight of Board W=85 N
length of board L=6 m
Rope B is connected from the other end of the board at a distance of 1.5
Box with a weight of 25 N is Placed on the board at distance of 1 m from Rope A
Let [tex]T_a[/tex] and [tex]T_b[/tex] be the Tension in the rope at side A and B
Now Taking moment about
[tex]85\times 1.5+25\times 3.5-T_a\times 4.5=0[/tex]
[tex]T_a=\frac{85\times 1.5+25\times 3.5}{4.5}[/tex]
[tex]T_a=\frac{215}{4.5}[/tex]
[tex]T_a=47.78 N[/tex]
